## RS Aggarwal Class 8 solutions Chapter 5 Playing with Numbers Ex 5D in pdf free download

Contents

**Question 1.**

**If 5×6 is exactly divisible by 3, then the least value of x is**

**(a)0**

**(b) 1**

**(c)2**

**(d) 3**

**Solution:**

5×6 is exactly divisible by 3

Sum of its digits must be divisible by 3

5 + x + 6 = 11 + x is divisible by 3

Least value of x = 1 as 12 is divisible by 3 (b)

**Question 2.**

**If 64y8 is exactly divisible by 3, then the least value of y is**

**(a)0**

**(b)1**

**(c)2**

**(d)3**

**Solution:**

64y8 is exactly divisible by 3 then the sum of its digits must be divisible by 3

6 + 4 + y + 8 or 18 + y is divisible by 3

Least value of y = 0

18 is divisible by 3 (a)

**Question 3.**

**If 7×8 is exactly divisible by 9, then the least value of x is**

**(a)0**

**(b)2**

**(c)3**

**(d)5**

**Solution:**

7 x 8 is exactly divisible by 9

Sum of its digits must be divisible by 9

7 + x + 8 = 15 + x must be divisible by 9

Least value of x = 3 as 15 + 3 = 18 is divisible by 9 (c)

**Question 4.**

**If 37y4 is exactly divisible by 9, then the least value of y is**

**(a)2**

**(b)3**

**(c)1**

**(d)4**

**Solution:**

37y4 is exactly divisible by 9

The sum of its digits must be divisible by

3 + 7 + y + 4 or 14 + y is divisible by 9

Least value of y = 4

As 14 + 4 = 18 is divisible by 9 (d)

**Question 5.**

**If 4xy7 is exactly divisible by 3, then the least value of (x + y) is**

**(a)1**

**(b)4**

**(c)5**

**(d)7**

**Solution:**

4xy7 is exactly divisible by 3

The sum of its digits must be divisible by 9

or 4 + x + y + 7 or 11 + (x + y) is divisible by 9

Least value of x + y = 7

as 11 + 7 = 18 is divisible by 9 (d)

**Question 6.**

**If x7y5 is exactly divisible by 3, then the least value of (x + y) is**

**(a)6**

**(b)0**

**(c)4**

**(d)3**

**Solution:**

x7y5 is exactly divisible by 3

Sum of its digits must be divisible by 3

x + 7 + y + 512 + (x + y) is divisible by 3

Least value of x + y = 0 as

12 + 0 = 12 is divisible by 3 (b)

**Question 7.**

**If x4y5z is exactly divisible by 9, then the least value of (x + y + z) is**

**(a)3**

**(b)6**

**(c)9**

**(d)0**

**Solution:**

x4y5z is exactly divisible by 9

The sum of its digits must be divisible by 9

x + 4 + y + 5 + z or 9 + (x + y + z) must be divisible by 9

Least value of x + y + z = 0 as 9 + 0 = 9 is divisible by 9 (d)

**Question 8.**

**If 1A2B5 is exactly divisible by 9, then the least value of (A + B) is**

**(a)0**

**(b)1**

**(c)2**

**(d)10**

**Solution:**

A2B5 is exactly divisible by 9

Sum of its digits must be divisible by 9

A + 2 + B + 5 = 7 + A + B is divisible by 9

Least value of A + B = 2 as 7 + 2 = 9 is divisible by 9

**Question 9.**

**If the 4-digit number x27y is exactly divisible by 9, then the least value of (x +y) is**

**(a)0**

**(b)3**

**(c)6**

**(d)9**

**Solution:**

x27y is exactly divisible by 9

The sum of its digits must be divisible by 9

x + 2 + 7 + y = x + y + 9 is divisible by 9

Least value of x + y = 0 as 0 + 99 is exactly divisible by 9 (a)

## Leave a Reply